∫e6log⁡x−e5log⁡xe4log⁡x−e3log⁡xdx is equal to

∫e6log⁡x−e5log⁡xe4log⁡x−e3log⁡xdx=∫elog⁡x6−elog⁡x5elog⁡x4−elog⁡x3dx=∫x6−x5x4−x3dx=∫x5(x−1)x3(x−1)dx=∫x2dt=x33+C∵log⁡mn=n log ⁡m