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e3logxx4+11dx=

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a
log⁡x4+1+c
b
14log⁡x4+1+c
c
−log⁡x4+1+c
d
None of these

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detailed solution

Correct option is B

I=∫e3log⁡xx4+1−1dx=∫elog⁡x3x4+1−1dx=14∫4x3x4+1dx=14log⁡x4+1+c


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