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0πesin2xcos3xdx is equal to

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a
-1
b
0
c
1
d
π

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detailed solution

Correct option is B

Let I=∫0π esin2⁡xcos3⁡xdx-----i⇒ I=∫0π esin2⁡(π−x)cos3⁡(π−x)dx⇒ I=−∫0π esin2⁡xcos3⁡xdx-----iiOn adding Eqs. (i) and (ii), we get2I=0 ⇒ I=0


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