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Q.

∫esin2x+cosx (sin2x−sinx) dx=

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a

e(sin2x+cosx)+C

b

e(sin2x−cosx)+C

c

e(sin2x−sinx)+C

d

e(sin2x+sinx)+C

answer is A.

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Detailed Solution

sin2x+cosx=t       (sin2x−sinx)dx=dt        ∫etdt=et+C                   =esin2x+cosx+C
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∫esin2x+cosx (sin2x−sinx) dx=