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Q.

∫etan⁡x(sin⁡x−sec⁡x)dx, is equal to

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a

etan⁡x⋅cos⁡x+C

b

etan⁡x⋅sin⁡x+C

c

−etan⁡x⋅cos⁡x+C

d

etan⁡x⋅sec⁡x+C

answer is C.

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Detailed Solution

I=∫etan⁡x(sinx-secx)dx=∫sin⁡x⋅etan⁡xdx−∫sec⁡x⋅etan⁡xdx=−etan⁡x⋅cos⁡x+∫cos⁡x⋅etan⁡x⋅sec2⁡xdx−∫sec⁡x⋅etan⁡xdx=−cos⁡x⋅etan⁡x+C
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