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$\int e^{\tan x} (\sin x - \sec x) d x =$

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etanx.cosx+C

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detailed solution

Correct option is C

∫etansin⁡xdx−∫etan⁡xsec⁡xdx (by parts) =−cos⁡xetan⁡x+∫cos⁡xetan⁡x⋅sec2⁡xdx−∫etan⁡xsec⁡xdx=−cos⁡x⋅etan⁡x+C

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∫etanxsinx−secxdx=

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$\int e^{\tan x} (\sin x - \sec x) d x =$