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excosexxdx=

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a
2sin⁡ex+c
b
sin⁡ex+c
c
2cos⁡ex+c
d
−2sin⁡ex+c

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detailed solution

Correct option is A

Put ex=t⇒exx=2dt⇒∫excos⁡exxdx=2∫cos⁡tdt=2sin⁡t+c=2sin⁡ex+c


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