∫$$ex2tan$$⁡$$x1+$$$$tan$$⁡$$x+cot2$$⁡$$x+$$π$$4dx$$ is equal to

Correct option is 2extan⁡x−π4+c

Questions

$\int e^{x} (\frac{2 \tan x}{1 + \tan x} + \cot^{2} (x + \frac{π}{4})) d x is equal to$

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extan⁡π4−x+c

extan⁡x−π4+c

extan⁡3π4−x+c

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detailed solution

Correct option is B

∫ex2tan⁡x1+tan⁡x+tan2⁡x−π4dx=∫extan⁡x−π4+sec2⁡x−π4dx=extan⁡x−π4+c

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∫ex2tan⁡x1+tan⁡x+cot2⁡x+π4dx is equal to

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$\int e^{x} (\frac{2 \tan x}{1 + \tan x} + \cot^{2} (x + \frac{π}{4})) d x is equal to$