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Q.

∫ex(1+tanx+tan2x)dx=

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a

exsinx+C

b

excosx+C

c

extanx+C

d

exsecx+C

answer is C.

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Detailed Solution

∫ex(1+tanx+tan2x)dx ∫ex(tanx+sec2x)dx                                 ∫ex(f(x)+f'(x)) dx =exfx=extanx+C
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