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ex1+xcos2xexdx.

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a
Tanxex+C
b
Cotxex+C
c
Cosx.ex+C
d
Sinx.ex+C

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detailed solution

Correct option is A

Letz=xex . Then dz=1ex+xexdx=ex(1+x)dx . Thus, ∫ex(1+x)cos2⁡xexdx=∫dzcos2⁡z=∫sec2⁡zdz=tan⁡z+c=tan⁡xex+c


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