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ex1x1+x22dx =

 

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a
ex1+x22
b
−xex1+x22
c
ex(1−x)1+x22
d
ex1+x2

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detailed solution

Correct option is D

ex1−x1+x22=ex11+x2−2x1+x22 so ∫ex1−x1+x2dx =∫ex1+x2dx−∫ex2x1+x22dx=ex1+x2+∫ex2x1+x22dx−∫ex2x1+x22dx+C=ex1+x2+C


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