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 ex1x1+x22dx is

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a
ex1+x22+c
b
−xex1+x22+c
c
ex(1−x)1+x22+c
d
ex1+x2+c

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detailed solution

Correct option is D

∫ex1−x1+x22dx=∫ex1+x2−2x1+x22dx=∫ex11+x2−2x1+x22dx=11+x2ex+∫ex2x1+x22dx−∫ex2x1+x22dx+C=ex1+x2+C


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