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Q.

∫ex1−x1+x22dx is

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a

ex1+x22+c

b

−xex1+x22+c

c

ex(1−x)1+x22+c

d

ex1+x2+c

answer is D.

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Detailed Solution

∫ex1−x1+x22dx=∫ex1+x2−2x1+x22dx=∫ex11+x2−2x1+x22dx=11+x2ex+∫ex2x1+x22dx−∫ex2x1+x22dx+C=ex1+x2+C
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