∫ex11+x2+1−2x21+x25dx
ex11+x2+x1+x23+C
ex11+x2−x1+x23+C
ex11+x2+x1+x25+C
ex11−x2−x1+x2+C
I=∫ex11+x2−x1+x23+x1+x23+1−2x21+x25dxI=ex11+x2+exx1+x23+CI=ex11+x2+x1+x23+C
∵ using ∫exf(x)+f′(x)dx=exf(x)+C