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ex11+x2+12x21+x25dx

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a
ex11+x2+x1+x23+C
b
ex11+x2−x1+x23+C
c
ex11+x2+x1+x25+C
d
ex11−x2−x1+x2+C

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detailed solution

Correct option is A

I=∫ex11+x2−x1+x23+x1+x23+1−2x21+x25dxI=ex11+x2+exx1+x23+CI=ex11+x2+x1+x23+C∵ using ∫exf(x)+f′(x)dx=exf(x)+C


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