Questions
is equal to
a
30C11
b
60C10
c
30C10
d
65C55
detailed solution
Correct option is C
Let A=3003010−3013011+3023012−…+30203030 or A=30C0⋅30C10−30C1⋅30C11+30C2⋅30C12−…+30C20⋅30C30 = Coefficient of x20 in (1+x)30(1−x)30= Coefficient of x20 in 1−x230= Coefficient of x20 in ∑r=030 (−1)r30Crx2r=(−1)10 30C10 [for coefficient of x20, let r=10=30C10=(−1)10 30C10 [for coefficient of x20, let r=10=30C10Talk to our academic expert!
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If the coefficients of P th, ( p + 1)th and (p + 2)th terms in the expansion of (1 + x)n are in AP, then
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