First slide
Algebra of vectors
Question

  a=4i^+3k^;b=14i^+2j^5k^  vectors  are laid off from one point. Vector d which is being laid off from the same point  dividing the angle between vector, a and b  in equal halves and having the magnitude 6, is

Moderate
Solution

a^=4i+3k^5;b^=14i^+2j^5k^15

 A vector V bisecting the angle between a and bis

V=a^+b^=12i^+9k^+14i^+2j^5k^15=2i^+2j^+4k^15

 Required vector d=6V^=i^+j^+2k^

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