∫log(x+1+x2)1+x2dx
12log(x+1+x2)2+c
log(x+1+x2)2+c
log(x+1+x2)+c
None of these
Let logx+1+x2 =tDifferentiating, we get1x+1+x21+2x21+x2dx=dt⇒11+x2dx=dt∴∫logx+1+x21+x2dx=∫t dt =t22+c =12logx+1+x22+c