First slide
Introduction to integration
Question

log(x+1+x2)1+x2dx

Moderate
Solution

  Let logx+1+x2 =tDifferentiating, we get1x+1+x21+2x21+x2dx=dt11+x2dx=dtlogx+1+x21+x2dx=t dt                                                   =t22+c                                                                                            =12logx+1+x22+c   

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