Q.

∫ln⁡(tan⁡x)sin⁡x⋅cos⁡xdx, is equal to

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a

12ln⁡(tan⁡x)+C

b

12ln⁡tan2⁡x+C

c

12(ln⁡(tan⁡x))2+C

d

None of these

answer is C.

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Detailed Solution

I=∫ln⁡(tan⁡x)sin⁡x⋅cos⁡xdx, let t=ln⁡(tan⁡x)⇒ dtdx=sec2⁡xtan⁡x⇒dt=dxsin⁡x⋅cos⁡x∴ I=∫tdt=12t2+C=12(ln⁡(tan⁡x))2+C
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∫ln⁡(tan⁡x)sin⁡x⋅cos⁡xdx, is equal to