Q.
∫ln(tanx)sinx⋅cosxdx, is equal to
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a
12ln(tanx)+C
b
12lntan2x+C
c
12(ln(tanx))2+C
d
None of these
answer is C.
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Detailed Solution
I=∫ln(tanx)sinx⋅cosxdx, let t=ln(tanx)⇒ dtdx=sec2xtanx⇒dt=dxsinx⋅cosx∴ I=∫tdt=12t2+C=12(ln(tanx))2+C
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