In−π$$2$$,π$$2$$,logsinθ$$cos2$$θ$$=2$$ has

Correct option is 2a unique solution

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In $(- \frac{π}{2}, \frac{π}{2}), \log_{\sin θ} (\cos 2 θ) = 2$ has

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Correct option is B

We have −π2≤θ≤π2. ∴−1≤sinθ≤1, here 0

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In−π2,π2,logsinθcos2θ=2 has

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In $(- \frac{π}{2}, \frac{π}{2}), \log_{\sin θ} (\cos 2 θ) = 2$ has