In−π2,π2,logsinθcos2θ=2 has
no solution
a unique solution
two solutions
infinitely many solutions
We have −π2≤θ≤π2. ∴−1≤sinθ≤1, here 0<sinθ<1 ∵sinθ is a base of logarithm ⇒0<θ<π2
Now, logsinθcos2θ=2⇒logsinθ1−2sin2θ=2 ⇒1−2sin2θ=sin2θ ⇒sinθ=13 ⇒θ is unique