First slide
Trigonometric equations
Question

Inπ2,π2,logsinθcos2θ=2 has

Easy
Solution

We have π2θπ2. 1sinθ1, here 0<sinθ<1   sinθ is a base of logarithm 0<θ<π2  

Now, logsinθcos2θ=2logsinθ12sin2θ=2  12sin2θ=sin2θ sinθ=13 θ is unique

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