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Q.

π2<α<π⇒1−cosα1+cosα+1+cosα1−cosα=

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a

2secα

b

−2secα

c

2cosecα

d

−2cosecα

answer is C.

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Detailed Solution

1+cosα+1-cosα1-cos2α= 2sin2α=2cosecα∵sinα is positive in II quadrant.
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π2<α<π⇒1−cosα1+cosα+1+cosα1−cosα=