Mean of the numbers 1, 2, 3,……,n with respective weights 12+1,22+2,32+3........,n2+n is
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a
3n(n+1)2(2n+1)
b
2n+13
c
3n+14
d
3n+12
answer is C.
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Detailed Solution
Here for each xi=i ,weight wi=i2+i Hence, the required mean =∑wixiwi=∑i=1ni(i2+i)∑i=1n(i2+i) =∑i=1ni3+∑i=1ni2∑i=1ni2+∑i=1ni =n2(n+1)24+n(n+1)(2n+1)6n(n+1)(2n+1)6+n(n+1)2 =n(n+1)2{n(n+1)2+2n+13}n(n+1)2{2n+13+1} =3n2+7n+22(2n+4) =(3n+1)(n+2)4(n+2)=3n+14