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$\int_{0}^{π / 2} min (\sin x, \cos x) d x$ equals to

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Correct option is C

∫0π/2 min(sin x,cos x)dx=∫0π/4 min(sin x,cos x)dx+∫π/4π/2 min(sin x,cos x)dx=∫0π/4 sin x dx+∫π/4π/2 cos x dx=−cos x0π/4+sin xπ/4π/2=−12−1+1−12=2−2

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∫0π/2 min(sin x,cos x) dx equals to

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$\int_{0}^{π / 2} min (\sin x, \cos x) d x$ equals to