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mxm+2n1nxn1x2m+2n+2xm+n+1dx is equal to

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a
xmxm+n+1+C
b
xnxm+n+1+C
c
xm+n−1xm+n+1+C
d
-xnxm+n+1+C

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detailed solution

Correct option is D

Let I=∫mxm+2n−1−nxn−1x2m+2n+2xm+n+1dx=∫mxm+2n−1−nxn−11+xm+n2dx∴I=∫mxm−1−nxn+1xm+1xn2dxLet  xm+1xn=t⇒mxm−1−nxn+1dx=dt∴I=∫1t2dt=−1t+C=−1xm+1xn+C=−xnxm+n+1+C


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