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Q.

∫mxm+2n−1−nxn−1x2m+2n+2xm+n+1dx is equal to

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a

xmxm+n+1+C

b

xnxm+n+1+C

c

xm+n−1xm+n+1+C

d

-xnxm+n+1+C

answer is D.

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Detailed Solution

Let I=∫mxm+2n−1−nxn−1x2m+2n+2xm+n+1dx=∫mxm+2n−1−nxn−11+xm+n2dx∴I=∫mxm−1−nxn+1xm+1xn2dxLet  xm+1xn=t⇒mxm−1−nxn+1dx=dt∴I=∫1t2dt=−1t+C=−1xm+1xn+C=−xnxm+n+1+C
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