a1,a2,a3…an are in A.P such that an=100,a50−a49=3/5 then 15th term of A.P from the end is

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4545

4485

4525

4585

answer is D.

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Detailed Solution

Let T15 is 15th term from end T15=an−14d=100-1435=100−425=4585

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