Q.

a1,a2,a3…an are in A.P such that an=100,a50−a49=3/5 then 15th  term of A.P from the end is

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a

4545

b

4485

c

4525

d

4585

answer is D.

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Detailed Solution

Let T15 is 15th  term from end T15=an−14d=100-1435=100−425=4585
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