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∑n=0∞(2i3)n=

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a

9+6i13

b

9−6i13

c

9 + 6i

d

9 – 6i

answer is A.

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Detailed Solution

∑n=0∞(2i3)n= 1+2i3+2i32+2i33+..... sum of infinite terms in G.P= a1-r = 11-2i3=33-2i= 33+2i3-2i3+2i=9+6i9+4=9+6i13

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