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Q.

34+1516+6364+…. to n terms =

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a

n−4n3−13

b

n+4−n3−13

c

n+4n3−13

d

n−4−n3+13

answer is B.

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Detailed Solution

For n = 1, we have n−4n3−13=1−43−13=−23n+4−n3−13=1+4−13−13=34n+4n3−13=1+43−13=2n−4−13+13=1−4−13+13=54Also, for n = 2, we have n+4−n3−13=2+148−13=2716and, 34+1516=2716Hence, option (b) is correct.ALITER We have,135+15.7+17.9+ ton terms =22−122+24−124+26−126+…… to n terms=1−122+1−124+1−126+… to n term−n−122+124+126+…to n term=n−1221−122n1−122=n−131−4−11=n+4−13−13
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