In0,π2, one solution of 3+1cosecx+3−1secx=42 is 5π12. If other solution is λπ36 then λ=
11
12
7
10
3+1cosecx+3−1secx=42⇒3+1cosx+3−1sinx=42sinxcosx⇒3+122cosx+3−122sinx=2sinxcosx⇒sinx+5π12=sin2x⇒2x=nπ+−1nx+5π12⇒x=5π12 or x=7π36⇒λ=7