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In0,π2, one solution of 3+1cosecx+31secx=42 is 5π12.   If other solution is λπ36 then λ=

a
11
b
12
c
7
d
10

detailed solution

Correct option is C

3+1cosecx+3−1secx=42⇒3+1cosx+3−1sinx=42sinxcosx⇒3+122cosx+3−122sinx=2sinxcosx⇒sinx+5π12=sin2x⇒2x=nπ+−1nx+5π12⇒x=5π12  or  x=7π36⇒λ=7

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