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Q.

In a ΔPQR, I is the in-centre and PI↔ cuts QR¯ at S . If Q=(–1, 2), R=(9, 7), PQ=14, PR=21 then S is

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a

(5, 5)

b

(4, 92)

c

(−215, −85)

d

(3, 4)

answer is D.

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Detailed Solution

Q(−1, 2), R(9, 7) QR100+25=25 PI cuts QR¯ at 's' In the ratioPQ:PR=14:21=2:3 S=2R+3Q2+3=(18, 14)+(−3, 6)5=(3, 4)

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