Questions
For cannot exceed
a
4nCn
b
4nC2n
c
6nC3n
d
none of these.
detailed solution
Correct option is B
For 0≤r<2n,(1+x)4n=(1+x)2n+r(1+x)2n−r=A0+A1x+A2x2+…+A2n+rx2n+rB0+B1x+B2x2+…+B2n−rx2n−r where Ak=2n+rCk(0≤k≤2n+r)and Bk=2n−rCk(0≤k≤2n−r)Coefficient of x2n on the RHSA2nB0+A2n−1B1+…+AnBn+An+1Bn−1+…+ArB2n−r = coefficient of x2n on LHS=4nC2n.Thus, AnBn<4nC2n ⇒ 2n+rCn 2n−rCn<4nC2nTalk to our academic expert!
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