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a
Cn+1 n+m+1
b
Cn n+m+2
c
Cn-1 n+m+3
d
None of these
answer is A.
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Detailed Solution
∑r=0mCn n+r=∑r=0mCr n+r ∵n+rCn=n+rCn+r−n=nC0+n+1C1+n+2C2+n+3C3+……+n+mCm Using, nC0=1=n+1C1= n+1C0+n+1C1+n+2C2+n+3C3+….+n+mCm Using this again and again, we are left =Cm n+m+1=Cn+1 n+m+1