For 2≤r≤n,(nr)+2(nr−1)+(nr−2) is equal to:
(n+1r−1)
2(n+1r−1)
2(n+2r)
(n+2r)
Expression =C(n,r)+2.C(n,r−1)+C(n,r−2)
=[C(n,r)+C(n,r−1)]+[C(n,r−1)+C(n,r−2)]
=C(n+1,r)+C(n+1,r-1)
=C(n+2,r)