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Q.

For 2≤r≤n,(nr)+2(nr−1)+(nr−2) is equal to:

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a

(n+1r−1)

b

2(n+1r−1)

c

2(n+2r)

d

(n+2r)

answer is D.

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Detailed Solution

Expression =C(n,r)+2.C(n,r−1)+C(n,r−2) =[C(n,r)+C(n,r−1)]+[C(n,r−1)+C(n,r−2)] =C(n+1,r)+C(n+1,r-1) =C(n+2,r)

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