First slide

Introduction to definite integration

Question

$\int (\sum_{r = 0}^{\infty} \frac{x^{r} . 2^{r}}{r!}) d x$

Easy

A

$e^{x} + C$
B

$\frac{1}{2} e^{2 x} + C$
C

$2 e^{2 x} + C$
D

$\frac{1}{2} e^{x} + C$

Solution

$\int \sum_{r = 0}^{\infty} \frac{{(2 x)}^{r}}{r!} d x = \int e^{2 x} d x = \frac{1}{2} e^{2 x} + C$

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