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a
13log sin3x-log sin5x+c
b
13log sin3x+15log sin5x+c
c
13log sin3x-15log sin5x+c
d
3log sin3x-5log sin5x+c
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Correct option is C
∫sin2xsin5xsin3xdx =∫sin(5x-3x)sin5xsin3xdx =∫sin5xcos3x-cos5xsin3xsin5xsin3xdx =∫(cot3x-cot5x)dx =13logsin3x-15logsin5x+cSimilar Questions
is equal to
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