First slide

Introduction to integration

Question

$\int \sec^{m} x . \tan x d x$ =

Moderate

A

$\frac{1}{m} \sec^{m} x + C$
B

$- \frac{1}{m} \sec^{m} x + C$
C

$\frac{1}{m} \tan^{m} x + C$
D

$\frac{1}{m + 1} . \sec^{m + 1} x + C$

Solution

$\int \sec^{m - 1} x (\sec x . \tan x) d x = \frac{\sec^{m} x}{m} + C$

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