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Evaluation of definite integrals
Question
∫
0
π
/
2
3
Sec
x
+
5
cos
e
c
x
Sec
x
+
cos
e
c
x
d
x
=
Easy
A
π
B
4
π
C
6
π
D
2
π
Solution
∫
0
π
2
3
S
e
c
x
+
5
C
o
s
e
c
x
S
e
c
x
+
C
o
sec
x
d
x
=
(
a
+
b
)
π
4
=
(
3
+
5
)
π
4
=
2
π
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