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secxdxcos2x=

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a
sin−1⁡(tan⁡x)+c
b
tan⁡x+c
c
cos−1⁡(tan⁡x)+c
d
sin⁡xcos⁡x+c

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detailed solution

Correct option is A

∫sec⁡xdxcos⁡2x=∫sec⁡xcos2⁡x−sin2⁡xdx                     =∫sec2⁡xdx1−tan2⁡xlet tanx=t   sec2xdx=dt=sin−1⁡(tan⁡x)+c


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