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sec2x7sin7xdx=

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a
tan⁡x(sin⁡x)7+C
b
cos⁡xsin7⁡x+C
c
sin⁡xcos7⁡x+C
d
None of these

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detailed solution

Correct option is A

I=∫sec2⁡x−7sin7⁡xdx=∫sec2⁡xsin7⁡xdx−7∫dxsin7⁡x=tan⁡xsin7⁡x+7∫tan⁡xcos⁡xsin8⁡xdx−7∫dxsin7⁡x=tan⁡xsin7⁡x+C


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