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$\int \frac{\sin^{4} x}{\cos^{2} x} d x = f (x) + \frac{1}{4} g (x) - \frac{3 x}{2} + c then g (x) / f (x) = ?$

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Correct option is A

∫sin4⁡xcos2⁡xdx=∫1−cos2⁡x2cos2⁡xdx=∫1−2cos2⁡x+cos4⁡xcos2⁡xdx=∫sec2⁡x−2+cos2⁡xdx=∫sec2⁡x−2+1+cos⁡2x2dx=∫sec2⁡x−32+12cos⁡2xdx=tan⁡x−3x2+14sin⁡2x+cf(x)=tan⁡x,&g(x)=sin⁡2x

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∫sin4⁡xcos2⁡xdx=f(x)+14g(x)−3x2+c then g(x)/f(x)=?

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$\int \frac{\sin^{4} x}{\cos^{2} x} d x = f (x) + \frac{1}{4} g (x) - \frac{3 x}{2} + c then g (x) / f (x) = ?$