First slide
Methods of integration
Question

sin5xcos4xdx=

Moderate
Solution

Im,nsinmxcosnxdx=sinm+1xcosn1m+n+n1m+nIm,n2

m=5,n=4

=sinm1xcosn+1xm+n+m1m+nIm2,n(m,nN,m2,n2)I5=sin5xcos4xdx=sin4xcos5x9+49I3,4=sin4xcos5x9+49sin2xcos5x7+27I1,4=sin4xcos5x9463sin2xcos5x+863sinxcos4xdx=sin4xcos5x9463sin2xcos5x8cos5x315+C

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