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a
−sin4xcos5x9+4sin2xcos5x63+cos5x315+C
b
sin4xcos5x9+4sin2xcos5x63+cos5x315+C
c
sin4xcos5x9−4sin2xcos5x63+cos5x315+C
d
−sin4xcos5x9−4sin2xcos5x63−8cos5x315+C
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Correct option is D
Im,n∫sinmxcosnxdx=sinm+1xcosn−1m+n+n−1m+nIm,n−2m=5,n=4=−sinm−1xcosn+1xm+n+m−1m+nIm−2,n(m,n∈N,m≥2,n≥2)I5=∫sin5xcos4xdx=−sin4xcos5x9+49I3,4=−sin4xcos5x9+49−sin2xcos5x7+27I1,4=−sin4xcos5x9−463sin2xcos5x+863∫sinxcos4xdx=−sin4xcos5x9−463sin2xcos5x−8cos5x315+CSimilar Questions
The value of is equal to
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