First slide
Evaluation of definite integrals
Question

0π2200sinx+100cosxsinx+cosxdx=

Easy
Solution

0π2200Sinx+100CosxSinx+Cosxdx  since 0π2aSinx+bCosxSinx+Cosxdx    ==(a+b)π4 

                              

                              =(200+100)π4

                              =75π

 

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