First slide

Evaluation of definite integrals

Question

$\int_{0}^{π} | \sin x | d x =$

Easy

A

0
B

1
C

2
D

$\frac{1}{2}$

Solution

$\int_{0}^{π} | S i n x | d x = \int_{0}^{π} S i n x d x = {(- C o s x)}_{0}^{π} = 2$

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