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Evaluation of definite integrals
Question
∫
−
2
π
2
π
Sin
5
x
.
d
x
=
Easy
A
0
B
3
π
16
C
8
15
D
27
16
Solution
∫
−
2
π
2
π
S
i
n
5
x
d
x
=
0
(
∵
f
(
x
)
i
s
o
d
d
f
u
n
c
t
i
o
n
)
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