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11+sinxdx=

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a
22log⁡tan⁡π8+x4+c
b
12log⁡tan⁡π8+x4+c
c
2log⁡tan⁡π8+x4+c
d
122log⁡tan⁡π8+x4+c

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detailed solution

Correct option is C

∫11+sin⁡xdx=∫11−cos⁡π2+xdx=∫12sin⁡π4+x2dx=12∫cosec⁡x2+π4dx=2log⁡tan⁡π8+x4+c


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