First slide

Evaluation of definite integrals

Question

$\int_{0}^{4 π} | \sin x | dx$ is equal to

Moderate

A

0
B

2
C

4
D

8

Solution

We know that, $|\sin x|$ is a periodic function of n.
Hence, $\int_{0}^{4 π} | \sin x | dx = 4 \int_{0}^{π} | \sin x | dx$
$= 4 \int_{0}^{π} \sin xdx = 4 [- \cos x]_{0}^{π} = 8$

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