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$\int_{0}^{4 π} | \sin x | dx$ is equal to

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Correct option is D

We know that, sin x is a periodic function of n.Hence, ∫04π |sin⁡x|dx=4∫0π |sin⁡x|dx =4∫0π sin⁡xdx=4[−cos⁡x]0π=8

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∫04π |sin⁡x|dx is equal to

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$\int_{0}^{4 π} | \sin x | dx$ is equal to