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$\int_{0}^{2 π} (\sin x + | \sin x |) dx$ is equal to

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Correct option is B

∫02π (sin⁡x+|sin⁡x|)dx=∫0π (sin⁡x+sin⁡x)dx+∫π2π (sin⁡x−sin⁡x)dx=∫0π 2sin⁡xdx+∫π2π 0dx=2[−cos⁡x]0π+0=−2(cos⁡π−cos⁡0)=−2(−1−1)=4

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∫02π (sin⁡x+|sin⁡x|)dx is equal to

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$\int_{0}^{2 π} (\sin x + | \sin x |) dx$ is equal to