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0π/2sin3/2xsin3/2x+cos3/2xdx is equal to

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a
0
b
π2
c
π4
d
None of these

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detailed solution

Correct option is C

Let,I=∫0π/2 sin3/2⁡xsin3/2⁡x+cos3/2⁡xdx----ithen  I=∫0π/2 sin3/2⁡π2−xsin3/2⁡π2−x+cos3/2⁡π2−xdx ∵∫0a f(x)dx=∫0a f(a−x)dx⇒I=∫0π/2 cos3/2⁡xcos3/2⁡x+sin3/2⁡xdx-----ii∵sin⁡π2−x=cos⁡x and cos⁡π2−x=sin⁡xOn adding Eqs. (i) and (iil, we get2I=∫0π/2 sin3/2⁡x+cos3/2⁡xsin3/2⁡x+cos3/2⁡xdx=∫0π/2 1dx=[x]0π/2=π2−0⇒I=π4


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