First slide
Methods of integration
Question

sin2xa2sin2x+b2cos2xdx

Easy
Solution

ddxa2sin2x+b2cos2x=a2b2sin2x Now, sin2xa2sin2x+b2cos2xdx=1a2b2a2b2sin2xa2sin2x+b2cos2xdx=1a2b2ddxa2sin2x+b2cos2xa2sin2x+b2cos2xdx=1a2b2loga2sin2x+b2 cos2x+C

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