First slide
Introduction to integration
Question

sin12x1+x2dx is equal to 

Moderate
Solution

I=sin12x1+x2dx, let x=tanθ dx=sec2θdθ I=sin12tanθ1+tan2θsec2θdθ=2θsec2θdθ =2(θtanθlnsecθ)+C =2xtan1xlnsectan1x+C

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