First slide
Evaluation of definite integrals
Question

01/2sin1x(1x2)3/2dx=

Easy
Solution

01/2Sin1x(1x2)3/2dx           t=sin1x

=0π/4tCos2tdt=0π/4tSec2tdt

                          =(tTant)0π/40π/4Tantdt

                           =π4(log1Cot1)0π/4

                         =π4log2

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