∫01/2sin−1x(1−x2)3/2dx=
π4+log2
π4−log2
π4−12log2
log2
∫01/2Sin−1x(1−x2)3/2dx t=sin−1x
=∫0π/4tCos2tdt=∫0π/4t Sec2t dt
=(t Tant)0π/4−∫0π/4Tan t dt
=π4−(log 1Cot1)0π/4
=π4−log2