First slide
Evaluation of definite integrals
Question

01sin1(2x1+x2)dx=

Easy
Solution

01Sin1(2x1+x2)dx=012Tan1xdx

                                   =2[Tan1x.x]0120111+x2xdx

                                   =2(π40)[log(1+x2)]01

                                   =π2log2

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