First slide
Methods of integration
Question

t4dt1t10is

Moderate
Solution

t4dt1t10dt=t4dt1(t5)2

t5=u5t4dt=du

 Use 1a2x2dx=12aloga+xax+c=15du12u2

=1512(1)log1+u1u+c

=110log1+t51t5+c

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